Question

A rectangle is 6 2/3 feet long and 3 1/5 wide.about how many feet is the distance around the rectangle

Answer 1

Hope this helps you!!!

Answer 2

Answer:

The distance around the rectangle is:

               $19\dfrac{11}{15}\ feet$

Step-by-step explanation:

The distance around the rectangle means the perimeter of the rectangle.

We know that for a rectangle width length l and width w the perimeter(P) is given by:

$P=2(l+w)$

Here we have:

$l=6\dfrac{2}{3}\ feet=\dfrac{20}{3}\ feet$

Also, the width is:

$w=3\dfrac{1}{5}\ feet=\dfrac{16}{5}\ feet$

Hence, the perimeter of rectangle is:

$P=2(\dfrac{20}{3}+\dfrac{16}{5})\\\\P=2(\dfrac{20\times 5+16\times 3}{15})\\\\P=2(\dfrac{100+48}{15})\\\\P=2\times \dfrac{148}{15}\\\\P=\dfrac{296}{15}\\\\P=19\dfrac{11}{15}\ feet$