Find the factorization of the polynomial below.

81x^2+7x+16

A. (9x + 8)(9x + 8)
B. (9x + 8)(9x - 8)
C. (9x + 4)(9x - 4)
D. (9x + 4)(9x + 4)

Respuesta :

OptionD is the answer..!!
Hope this helps u.!!
Ver imagen rachelpinto17

Answer:

The given Polynomial is

   [tex]\rightarrow 81x^2+7x+16[/tex]

                                     ------------------------------(1)

Comparing with general equation of Quadratic

    ax²+bx+c=0

The roots or factorization of this polynomial is possible only when

    [tex]D\geq b^2-4ac[/tex]

In equation 1,

 [tex]D=(7)^2-4 \times 81 \times 16\\\\D=49-5184\\\\D= -5135\\\\D<0[/tex]

So, Real factors of this Polynomial is not Possible.

Complex roots is given by

     [tex]\rightarrow x=\frac{-b\pm \sqrt{D}}{2a}\\\\x=\frac{-7 \pm \sqrt{-5135}}{2 \times 81}\\\\x=\frac{-7 \pm\sqrt{-5135}}{162}[/tex]