Question

1-20 evaluate the expression below of the given values. If you can explain it to me i’m so appreciated

Answer 1

To solve 1-20, you plug in the number for the variable that the variable is equal to e.i. a) x = -3 so you plug -3 in every place there is an x

-2(-3)^2 - 3(-3) + 1

-2(9) +9 + 1

-18 +10

-8
The solution to a) is -8.

Please leave a comment and let me know if you also need help with b-d or if you understand.

Answer 2

Answer:

a) -8

b) -56

c) 3

d) 6

Step-by-step explanation:

(a). The expression is given by,

$\Rightarrow -2x^2-3x+1$

Now, substitute the the value of x = 3 in the expression

$\Rightarrow -2\times(-3)^2-3\times(-3)+1$

$\Rightarrow -8$

(b). The expression is given by,

$\Rightarrow 8-(3x-2)^2$

Now, substitute the the value of x = -2 in the expression

$\Rightarrow 8-(3\times(-2)-2)^2$

$\Rightarrow -56$

(c). The expression is given by,

$\Rightarrow \dfrac{-3}{k+2}$

Now, substitute the the value of k = -3 in the expression

$\Rightarrow \dfrac{-3}{-3+2}$

$\Rightarrow 3$

(d). The expression is given by,

$\Rightarrow \dfrac{15m}{n+1}-m^2+n$

Now, substitute the the value of m = 1 and n = 2 in the expression

$\Rightarrow \dfrac{15\times1}{2+1}-1^2+2$

$\Rightarrow 6$

Hence, This is the required solution.