figure#0 has 4 tiles figure#1 has 9 tiles figure#2 has 16 figure #3 has 25 tiles figure#4 has 36 tiles figure#5 has 49 tiles how many will figure #100 have,and what is the rule that will give the number of tiles in any figure in the pattern.

Go back to figure 1. There is a square in the middle of the drawing. The square consists of 4 tiles. Draw them on a piece of paper. I can't reproduce them, but it looks like every drawing has a square with (n + 1)^2 tiles in it.

Look at figure 2. There is a square in the middle of the drawing. The figure number plus 1 all squared = the number of tiles in that square. t = (f + 1)^2. You should be able to see 9 squares in that central square.

Three will give you 16 squares in the middle square.

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Now there are arms coming off the square. Again each arm is related to the figure number.

In figure 1 the arm length is 2 tiles. It suggests 2*f is the number of tiles in both arms together.

Figure 2 has 3 tiles in each arm. That means that the total number of tiles used for 1 arm (f + 1) = (2 + 1) = 3

Figure 3 has 4 tiles in each arm. Total 8.

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Finally all figures have 1 tile sitting on top of everything else. No more than 1 and no less than 1. Just 1.

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Now we are ready to talk about figure 100.

The square in the middle was determined to be (f + 1)^2 = 101^2 = 10201

The arms were determined to be t = 2 *( f + 1) = 2 * 101 = . . . . .. . . . . .202

And there is one more square that every figure has . . . . . . . . . . . . . . . ..1

Total . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .10404

Just what we got before. If you need more, leave a note about what you need, in detail.