Enzo156
contestada

A regular pasture has a fence around the perimeter. The length of the fence is 16x^7 and the width is 48x^4. What is the area of the pasture
A) 3x^3
B) 128x^11
C)768x^11
D)768x^28

Respuesta :

So a regular pasture is rectangular, and the area of a rectangle is [tex] A=lw [/tex] . Using the info that we can form our equation as [tex] A=16x^7(48x^4) [/tex]

Now the rule with multiplying exponents of the same base is to add the exponents together. Using this rule here, we can solve it as such:

[tex] A=16x^7(48x^4)\\ A=(16*48)x^{7+4}\\ A=768x^{11} [/tex]

In short, your answer is going to be C. 768x^11.