Let's look at the terms of the sequence for different values of n, starting from 0.
a₀ = 0/1 = 0
a₁ = 1/(1 +1) = 1/2
a₂ = 2/(2 + 1) = 2/3
a₃ = 3/(3 + 1) = 3/4
a₄ = 4/5
a₅ = 5/6
a₆ = 6/7
a₇ = 7/8
a₈ = 8/9
a₉ = 9/(9+1) = 9/10
a₁₀ = 10/(10+1) = 10/11 and so on
Let's look at the terms. As n gets bigger the terms gets closer to 1. We started with 0, then to one half, then two thirds, and as we get larger and larger, the terms are getting closer to 1. Let's choose a really big n and see.
a₉₉₉ = 999/(999 + 1) = 999/1000
Or an even bigger n:
a₉₉₉₉₉₉₉₉₉ = 999999999/(999999999 + 1) = 999999999/1000000000ⁿ
So as n gets really really large - and close to infinity - the terms get closer to 1.
