Respuesta :
The total space needed is 600 feet. Because 5 tables times 72 feet is 360 and 5 tables times 48 feet a part is 249. You add them and it comes out to be 600. It should be worked out like this 5(72+48)
Okay assuming I understand the question right, there are 5 tables running 72 inches long with 48 inches in between. If x is a table, and o is space, how can we arrange 5 x's with a space in between? xoxoxoxox. Note how we only use 4 o's for 5x's. We don't need space outside of the tables, just in between them.
With this, let's do some math. If we have 5 x's, that's 5 tables, which means that our length from the tables are going to be [tex]5*72=360[/tex] inches.
We have 4 spaces, at 48 inches each is going to take up [tex]4*48=192[/tex]
Adding up both, [tex]192+360=552 inches[/tex].
552 inches of length is needed.