Question

What is the equation of the line with m = 6 that goes
through the point (1, 4)?

Answer 1

$\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad \qquad \qquad slope = m\implies 6 \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-4=6(x-1) \\\\\\ y-4=6x-6\implies y=6x-2$