Respuesta :

[tex] 4(x+1)>-4 \vee 2x-4\leq-10\\
4x+4>-4 \vee 2x\leq -6\\
4x>-8 \vee x\leq -3\\
x>-2 \vee x\leq -3\\
x\in(-\infty,-3] \cup (-2,\infty) [/tex]