Question

Partially factored form: f(x) = (x − 3)(x + 3)(x2− 4x + 5) Use the quadratic formula to identify the zeroes of x2 − 4x + 5. x =

Answer 1

The quadratic formula tells you that the solutions to

$ax^2+bx+c=0$

are given by

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

Filling in a=1, b=-4, c=5, this becomes

$x=\dfrac{-(-4)\pm\sqrt{(-4)^2-4(1)(5)}}{2\cdot 1}\\\\x=\dfrac{4\pm\sqrt{-4}}{2}\\\\x=2\pm i$

The zeros are 2+i andd 2-i.

Answer 2

Answer:

x=2+i and 2-i