Question

How many 100 dollar bills will fit in a cubic foot?

Answer 1

First of all, we need to compute the volume of a 100 dollars bills. A quick search on Google tells us that

"The $100 bill is the same size as all other US currency. All US paper currency is 2.61 inches wide and 6.14 inches long, 0.0043 inches thick and weigh 1 gram"

So, since the bill is a rectangular prism, its volume is given by the product of its three dimensions. So, you have

$V = 2.61 \times 6.14\times 0.0043 = 0.06890922$ cubed inches.

Now, the volume of the bill is expressed in cubic inches, while the volume of the container is expressed in cubic foot. We need a conversion, and since there are 12 inches in 1 foot, there are $12^3 = 1728$ cubic inches in a cubic foot.

So, we have a volume of 1728 cubic inches, and we want to know how many 0.06890922-cubed-inched bills we can fit in it.

Since one bill has a volume of 0.06890922 cubic inches, $k$ bills have a volume of $0.06890922k$. We want to choose $k$ in such a way that it fill a 1728 cubic inches volume, so the equation is

$0.06890922k = 1728 \iff k = \dfrac{1728}{0.06890922} \approx 25076.47$

So, about 25 thousands bills would fit in a cubic foot.

Answer 2

25,080 bills of 100 dollars will fit in a cubic foot.

Given we have a 100 dollar bills or a note.

We have, length of 100 dollar bills is  6.14 inches and breadth is 2.61 inches and the thickness of the bill is 0.0043 inches.

We know that, the volume of one 100 dollar bills will be,

$V=L\times B\times T$

$V=6.14\times 2.61\times 0.0043$

$V=0.06890922$

Now the volume of one 100 dollar bills is 0.068909 cubic inches.

Since one cubic foot is equal to 1728 cubic inches, So the no. of 100 dollar bills fit in a cubic foot will be,

$N=\frac{1728}{0.06890922}$

$N=25079.8258345$

Hence Approximately 25,080 bills of 100 dollars will fit in a cubic foot.

For more details on Volume calculation follow the link:

https://brainly.com/question/1578538