Graph the function.
y = 1/5 (3)^x
Graph A. B. C. or D?
![Graph the function y 15 3x Graph A B C or D class=](https://us-static.z-dn.net/files/d15/7621d55f3287c558e9067334abc0d389.jpg)
![Graph the function y 15 3x Graph A B C or D class=](https://us-static.z-dn.net/files/de2/599e33dc003322f1e72d4a19cdcc6afb.jpg)
![Graph the function y 15 3x Graph A B C or D class=](https://us-static.z-dn.net/files/de4/b0ce0615c50d64c0ef3bdb7cf2fb1e7d.jpg)
![Graph the function y 15 3x Graph A B C or D class=](https://us-static.z-dn.net/files/d0d/cde0b21a717c5d9822c9bcebac523c02.jpg)
The function [tex] y=3^x [/tex] is incresing and have positive values for all x. Then the function [tex] y=\dfrac{1}{5}\cdot 3^x [/tex] is also increasing and have positive values for all x. This means that options B (values are negative) and D (function is decreasing) are incorrect.
At x=0, [tex] y=\dfrac{1}{5} \cdot 3^x=\dfrac{1}{5} \cdot 3^0=\dfrac{1}{5} \cdot 1=\dfrac{1}{5} [/tex].
In option A graph of the function passes through point (0,y), where y is near 3. In option C graph of the function passes through point (0,y), where y is near 1/5. So, you can conclude that the option C is correct.