Respuesta :
To see, we should use the quadratic formula:
(-b +/- sqrt (b - 4ac))/2a
We plug the values in:
(-(-4) +/- sqrt (-4 - 4 * 3 * 5))/(2 * 3)
(4 +/- sqrt (-64))/6
But, we can’t have a negative square root, so we use i for imaginary.
That means that we will have imaginary roots, so the answer is (D).
Answer:
Option D is the correct answer.
Step-by-step explanation:
Properties of roots of ax²+bx+c=0 are decided by discriminant b²- 4ac
If b²- 4ac > 0 real and distinctive roots
If b²- 4ac = 0 equal roots
If b²- 4ac < 0 imaginary roots
We have 3x²-4x+5=0
a = 3, b = -4 and c = 5
b²- 4ac = (-4)²-4 x 3 x 5 = 16 - 60 = -44 < 0
So roots are imaginary.
Option D is the correct answer.