Question

CHEM AGAIN

Methanol (CH3OH) is an important industrial compound that is produced from the reaction:

CO(g)+H2(g)—> CH3OH(g)

What mass of CO would be needed to produce 208 kg of methanol?

Answer 1

Answer:-

182 Kg

Explanation:-

Molar mass of CO = 12 x 1 + 16 x 1 = 28 grams

Molar mass of CH3OH = 12 x 1 + 1 x 3 + 16 x 1 + 1 x 1

= 32 grams

The balanced equation for this reaction is

CO(g)+H2(g)—> CH3OH(g)

From the equation we see

1 CH3OH is produced from 1 CO

32 grams of CH3OH is produced from 28 grams of CO.

208 Kg of CH3OH is produced from (28 gram x 208 Kg) / (32 gram)

= 182 Kg of CO