Respuesta :

The nth term of the arithmetic series is given by

[tex] a_n=-5(n-1)+8 [/tex]

Now find the first five terms [tex] a_1, a_2, a_3, a_4, a_5: [/tex]

[tex] a_1=-5(1-1)+8=8 [/tex]

[tex] a_2=-5(2-1)+8=3 [/tex]

[tex] a_3=-5(3-1)+8=-2 [/tex]

[tex] a_4=-5(4-1)+8=-7 [/tex]

[tex] a_5=-5(5-1)+8=-12 [/tex]

Thus the first five terms of the series is [tex] 8,3,-2,-7,-12. [/tex]

Now find the partial sum of the series:

[tex] S_1=a_1=8 [/tex]

[tex] S_2=a_1+a_2=8+3=11 [/tex]

[tex] S_3=a_1+a_2+a_3=8+3-2=9 [/tex]

[tex] S_4=a_1+a_2+a_3+a_4=8+3-2-7=2 [/tex]

[tex] S_5=a_1+a_2+a_3+a_4+a_5=8+3-2-7-12=-10


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