To find which x coordinate makes f(x) = g(x) or to find when those lines intersect, we need to set them equal: [tex] - {x}^{2} + 4x + 12 = - x + 6[/tex]
Add x-6 to both sides of the equation: [tex] - {x}^{2} + 5x + 6 = 0[/tex]
Make [tex] - {x}^{2} [/tex] positive by multiplying the equation by -1: [tex] {x}^{2} - 5x -6 = 0[/tex]
Now find the x using quadratic formula: [tex]x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} [/tex]
Plug the values: [tex]x = \frac{ - ( - 5)\pm \sqrt{ { (- 5)}^{2} - 4 \times 1 \times - 6 } }{2 \times 1} [/tex]
Simplify:
[tex]x = \frac{5 \pm \sqrt{25 + 24} }{2} = \frac{5\pm \sqrt{ 49} }{2} [/tex]
Now we need to branch the plus-minus sign:
[tex]x = \frac{5 + 7}{2} = \frac{12}{2} =6[/tex]
[tex]x = \frac{5 - 7}{2} = \frac{ - 2}{2} = - 1[/tex]
Because -1 isn't in the choices, 6 is the right answer.