Respuesta :
Line is divided into 4 equal parts.
we have to find a point which is closest to point A.
So that means required point P(x,y) is at 1 unit away from A(-1,1) and 3 unit away from B(8,4)
Now we just need to use section formula to get the coordinate of required point using m1=1 and m2=3
[tex] \left ( \frac{m_1x_2+m_2x_1}{m_1+m_2} , \frac{m_1y_2+m_2y_1}{m_1+m_2} \right ) [/tex]
[tex]= \left ( \frac{1*8+3*(-1)}{1+3} , \frac{1*4+3*1}{1+3} \right ) [/tex]
[tex]= \left ( \frac{8-3}{4} , \frac{4+3}{4} \right ) [/tex]
[tex]= \left ( \frac{5}{4} , \frac{7}{4} \right ) [/tex]
So the final answer is [tex]\left ( \frac{5}{4} , \frac{7}{4} \right ) [/tex].