Question

(-3/2x4/5)+(9/5-10/3)-(1/2x3/4)

Answer 1

will solve the equation separately and will add together

$-3/2*4/5=-12/10$

$9/5-10/3=27-50$

here i have taken the common denominator so the denominator becomes 50

$-1/2*3/4=-3/8$

now we have to add these three terms

$-12/10-23/50-3/8=-240-92-75/200=-407/200$

here i have taken common denominator for 5,10 and 8

will get 200 as common denominator .so the final expression will be -407/200

Answer 2

$\left ( \frac{3}{2}\times \frac{4}{5} \right )+\left ( \frac{9}{5}- \frac{10}{3} \right )-\left ( \frac{1}{2}\times \frac{3}{4} \right )$

In the first parenthesis, multiply the numerators so we get -12 and after multiply the denominator we will get 10

So the fraction in the first parenthesis will be $\left ( \frac{-12}{10} \right )$

To solve the 2nd parenethesis, find the LCD of the denominator.

So the LCD of 5 and 3 = 15,

Now make the each denominator same as that of LCD.

So the new fractions in the 2nd parenthesis = $(\left ( \frac{27}{15}- \frac{50}{15} \right )$ = $\left ( \frac{-23}{15} \right )$

In the third parenthesis, multiply the numerators so we get 3 and after multiply the denominator we will get 8

So third parenthesis = $\left ( \frac{3}{8}\ \right )$

= $\left ( \frac{-12}{10} \right ) + \left ( \frac{-23}{15} \right ) -\left ( \frac{3}{8}\ \right )$

LCD of 12,15 and 8 is 120

=$\left ( \frac{-144}{120} \right ) + \left ( \frac{-184}{120} \right ) -\left ( \frac{45}{120}\ \right )$

=$\left ( \frac{-373}{120} \right )$