A construction crew must build 3 miles of road in one week. On Monday, they build 2/3 mile of road. On Tuesday, they build 1/4 mile of a road. How many miles of road do they still have to build thus week?

So first we need to find how much road they have built already this week (on Monday and Tuesday).
We are told that Monday they built [tex] \frac{2}{3} [/tex] mile and on Tuesday they built [tex] \frac{1}{4} [/tex] mile. So let's add them together. We'll use a denominator of 12, since that is a common factor to both of them. What you do to the bottom of the fraction you must do to the top:
[tex] \frac{2}{3}=\frac{8}{12} [/tex]
[tex] \frac{1}{4}=\frac{3}{12} [/tex]
So now that we have a common denominator, we can add them together:
[tex] \frac{8}{12}+\frac{3}{12}=\frac{8+3}{12}=\frac{11}{12} [/tex]
They built [tex] \frac{11}{12} [/tex] mile of road so far this week. If they need to build 3, we need to subtract [tex] \frac{11}{12} [/tex] from 3 to find how much remains. Let's get 3 to a number of 12 so we have a common denominator:
[tex] \frac{3}{1}=\frac{36}{12} [/tex]
Now let's subtract:
[tex] \frac{36}{12}- \frac{11}{12}= \frac{25}{12}=2\frac{1}{12} [/tex]
So now we know that the amount of road left that they must build this week is [tex] 2\frac{1}{12} [/tex] mile.