Respuesta :
we are given
[tex] (3x^2 y)^{-3} [/tex]
firstly , we can make exponent positive
[tex] \frac{1}{(3x^2y)^3} [/tex]
now, we can distribute exponent
[tex] \frac{1}{(3x^2)^3(y)^3} [/tex]
[tex] \frac{1}{(3)^3(x^2)^3(y)^3} [/tex]
we can combine exponents
and we get
[tex] \frac{1}{27x^6y^3} [/tex]...........Answer
[tex] (3x^{2}y)^{-3}
=\frac{1}{(3x^{2}y)^{3}}
= \frac{1}{27x^{6}y^{3}} [/tex]
