Can someone please help me with this. Thank you

The formula for conditional probability is as following:
P(A/B')=P(A∩B') /P(B')
Given P(A ∩ B')=[tex] \frac{1}{6} [/tex] and P(B')=[tex] \frac{7}{24} [/tex].
So, first step is to plug in the given values in the above formula to get the answer. Hence,
P(A/B')=[tex] \frac{\frac{1}{6}}{\frac{7}{24}} [/tex]
=[tex] \frac{\frac{1}{6}*24}{\frac{7}{24}*24} [/tex]
(Multiplying both top and bottom by 24).
=[tex] \frac{4}{7} [/tex]
So, P(A/B')=[tex] \frac{4}{7} [/tex]
Hence, the correct choice is B: [tex] \frac{4}{7} [/tex]