The base of a parallelogram is 7 ft more than the height. If the area of the parallelogram is 60ft square, what are the measures of the base and the height?

The height of the parallelogram is 5 ft and the base of the parallelogram is 14 ft and this can be determined by forming the quadratic equation by using the given data.
Given :
Let the height of the parallelogram be 'x' then the base of the parallelogram is (x + 7).
The area of the parallelogram is given by the formula:
[tex]\rm A=H\times B[/tex]
where A is the area, B is the Base and H is the height of the parallelogram.
Now, substitute the values of known terms in the above formula.
[tex]60=x(x+7)[/tex]
Simplify the above expression in order to determine the value of 'x'.
[tex]x^2 +7x -60=0[/tex]
By using the quadratic formula the factors of the above equation can be determined.
[tex]x = \dfrac{-7\pm\sqrt{7^2+4\times60} }{2}[/tex]
Simplify the above expression.
[tex]x = \dfrac{-7\pm 17}{2}[/tex]
x = -12 or 5
'x' is never negative. So, the value of 'x' is 5 ft.
The base of the parallelogram is (7+7) 14 ft.
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https://brainly.com/question/1563728