Question

What is the mass of 2.56 × 10–4 moles of Fe2O3?

Answer 1

Answer:

4.09 × 10⁻² g

Solution:

As we know that,

1 mol of Fe₂O₃ is equal to = 159.69 g

So,

2.56 × 10⁻⁴ mol will be equal to = X g

Solving for X,

X = (159.69 g × 2.56 × 10⁻⁴ mol) ÷ 1 mol

X = 0.04088 g

Or,

X = 0.049 g

Or,

X = 4.09 × 10⁻² g

Answer 2

The answer is 4.09 x 10^-2g

Hope this helps!