[tex] \dfrac{\dfrac{x}{4}+\dfrac{1}{8}}{\dfrac{x^2}{4}}=\left(\dfrac{2\cdot x}{2\cdot4}+\dfrac{1}{8}\right):\dfrac{x^2}{4}=\left(\dfrac{2x}{8}+\dfrac{1}{8}\right)\cdot\dfrac{4}{x^2}\\\\=\dfrac{2x+1}{8}\cdot\dfrac{4}{x^2}=\dfrac{2x+1}{2}\cdot\dfrac{1}{x^2}=\dfrac{2x+1}{2x^2}\to A. [/tex]
