Question

The product of two consecutive integers is 420 An equation is written in standard form to solve for the smaller integer by

factoring
What is the constant of the quadratic expression in this equation?
x2 +x+

0

Answer 1

The constant is zero. Hope I helped.

Answer 2

Answer:

$-420$

Explanation:

if we call the fist of the numbers $x$, then the following number is $x+1$.

the product of this two numbers according to the problem is:

$(x)(x+1)=420$

which results in:

$x^2+x=420$

The standar form of a quadratic equation is

$Ax^2+Bx+C=0$

so we must make the equation equal to zero: $x^2+x-420=0$

and this way we can see that the constant $C$ in the quadratic expression is $-420$.

if you want the values of the consecutive numbers, they are 20 and 21.