how do I solve 17 to 20
you don't have to do 18

[tex] 17)\\10(x+3)-(-9x-4)=x-5+3\ \ |\text{use distributive property}: a(b+c)=ab+ac\\\\10x+30+9x+4=x-2\\\\19x+34=x-2\ \ \ |-34\\\\19x=x-36\ \ \ |-x\\\\18x=-36\ \ \ |:18\\\\\boxed{x=-2} [/tex]
[tex] 19)\\-12(x-12)=-9(1+7x)\ \ |\text{use distributive property}: a(b+c)=ab+ac\\\\-12x+144=-9-63x\ \ \ |-144\\\\-12x=-153-63x\ \ \ |+63x\\\\51x=-153\ \ \ |:51\\\\\boxed{x=-3} [/tex]
[tex] 20)\\-11+10(p+10)=4-5(2p+11)\ \ |\text{use distributive property}: a(b+c)=ab+ac\\\\-11+10p+100=4-10p-55\\\\10p+89=-10p-51\ \ \ |-89\\\\10p=-10p-140\ \ \ |+10p\\\\20p=-140\ \ \ |:20\\\\\boxed{p=-7} [/tex]