Answer:
The correct option is A.
Step-by-step explanation:
Given: ΔABC
Prove: Mid segment between sides AB and BC is parallel side AC.
Let the vertices of triangle are A(0,0), B(x₁,y₁) and C(x₂,0).
Midpoint Formula:
[tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]
The midpoint of AB is
[tex]D=(\frac{0+x_1}{2},\frac{0+y_1}{2})[/tex] (Using the midpoint formula)
The midpoint of AB is
[tex]E=(\frac{x_1+x_2}{2},\frac{0+y_1}{2})[/tex] (Using the midpoint formula)
Slope Formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
The slope of DE is
[tex]m=\frac{\frac{0+y_1}{2}-\frac{0+y_1}{2}}{\frac{x_1+x_2}{2}-\frac{0+x_1}{2}}=0[/tex]
The slope of AC is
[tex]m=\frac{0-0}{x_2-x_0}=0[/tex]
Slope of AC and DE are same, therefore the lines AC and DE are parallel because slope of two parallel lines are same.
The correct statement is "The coordinates of D and E were found using the midpoint formula".
Therefore the correct option is A.