The balanced equation for the reaction between HBr and LiOH is as follows
HBr + LiOH —> LiBr + H2O
Stoichiometry of HBr to LiOH is 1:1
The number of LiOH moles reacted - 0.205 mol/L x 0.02915 L = 0.00598 mol
The number of HBr moles reacted = number of LiOH moles reacted
Therefore the number of HBr moles reacted = 0.00598 mol
If 25.0 mL of HBr contains - 0.00598 mol
Then 1000 mL of HBr contains - 0.00598 / 25.0 mL x 1000 mL = 0.239 mol
The molarity of HBr is -0.239 mol/L
