Respuesta :
step 1
find the slope AB
A = (-3, -1) and B = (4, 4)
m=(y2-y1)/(x2-x1)------> m=(4+1)/(4+3)------> m=5/7
step 2
find the slope mBC
we know that
if two lines are perpendicular
then
the product of their slopes is equal to -1
so
mAB*mBC=-1-------> mBC=-1/mAB-----> -1/(5/7)-----> mBC=-7/5
step 3
with mBC and the point B = (4, 4) find the equation of the line BC
y-y1=m*(x-x1)-----> y-4=(-7/5)*(x-4)-----> y=-(7/5)*x+(28/5)+4---> y=-(7/5)*x+(48/5)
y=-1.4*x+9.6
therefore
the answer is
the equation of the line BC is
y=-1.4*x+9.6
see the attached figure
![Ver imagen calculista](https://us-static.z-dn.net/files/dd2/ff2d4a57f358d28eb9e8eb0d12b0cbb2.jpg)
Answer:
-7x − 5y = -48
Step-by-step explanation:
This was correct on plato :D