Respuesta :
Answer:
353 and 439 tickets.
Step-by-step explanation:
Total number of tickets sold = 792
Let Box office one sold tickets be x
Box office two sold tickets = x + 86
Total tickets sold = x + (x+86) = 792
= 2x + 86 = 792
= 2x = 792 - 86
= 2x = 706
x = 353
One box office sold 353 tickets, As per given statement that "second box office sold 86 more tickets"
Box office two sold 353 + 86 = 439 tickets
Therefore, one box office sold 353 and other box office sold 439 tickets.
According to the question, we have two box offices which can be represented as:
A
B = Box office that sold 86 more tickets A. This statement is represented algebraically as : A + 86
The total number of tickets sold = 792
Hence, our Algebraic expression = A + B = 792
Note: B = A + 86
A + A + 86 = 792
2A + 86 = 792
Collect like terms
2A = 792 - 86
2A = 706
Divide both sides by 2
2A/2 = 706/2
A = 353 tickets
Solving for B
B = A + 86 = 353 + 86
B = 439 tickets
Therefore,
Box office A sold 353 tickets
Box office B sold 439 tickets
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https://brainly.in/question/26682188?tbs_match=1
