Respuesta :
It is nonequivalent. Figure it out this way. Think about what number has to be multiplied by both the numerator and the denominator of [tex] \frac{5x}{25x^4} [/tex] to get to [tex] \frac{x^3}{5x^15} [/tex]. It has to be the samee number for the one expression to be equivalent to the other. To get from 5x to x^3, we have to multiply by 1/5x^2. When we do that we get x^3. Good. Now we have to multiply the denominator by the same thing, 1/5x^2. [tex] 25x^4(\frac{1}{5}x^2)=5x^6 [/tex]. As you can see, they are not equivalent.
For this case we have the following expressions:
[tex] \frac{5x}{25x^4} [/tex]
[tex] \frac{x^3}{5x^{15}} [/tex]
We can rewrite both expressions using properties of powers.
For power properties we have:
"In a division, if we have the same base, we subtract the exponents"
Rewriting both expressions we have:
[tex] \frac{5x}{25x^4} = \frac{1}{5}x^{1-4} = \frac{1}{5}x^{-3} = \frac{1}{5x^3} [/tex]
[tex] \frac{x^3}{5x^{15}} = \frac{1}{5}x^{3-15} =\frac{1}{5}x^{-12} = \frac{1}{5x^{12}} [/tex]
Answer:
True.
Rational expressions are not equivalent.