A builder set up a wooden frame in which to pour concrete for a foundation to a house. the length of the wooden frame is 24 feet. The width is 32 feet. The diagonal is 40 feet. Which best describes the foundation?
![A builder set up a wooden frame in which to pour concrete for a foundation to a house the length of the wooden frame is 24 feet The width is 32 feet The diagona class=](https://us-static.z-dn.net/files/dea/6a8ef9edcc07ba0cb8c8a8cced865da5.png)
The answer is the last option, which is: The foundation may be a rectangle: [tex] 24^{2}+ 32^{2} =40^{2} [/tex]
The explanation for this problem is shown below:
1- A rectangle is defined as a parallelogram whose opposite sides are parallel and congruent. Its interior angles are right angles.
2- Keeping the definition above on mind, the diagonal of a rectangle divides it into to right triangles. So, we can verify if the shape of the frame is a rectangle by using the Pythagorean Theorem, which is:
[tex] a^{2}= b^{2} +c^{2} [/tex]
Where [tex] a [/tex] is the hypotenuse (the measure of the diagonal) and [tex] b [/tex] and [tex] c [/tex] are the other sides of the right triangle.
3- Therefore, you have that [tex] a [/tex] must be equal to [tex] 40 [/tex] to conclude that it is a rectangle:
[tex] \\a=\sqrt{24^{2}+32^{2}} \\ a=40 [/tex]
4-So, as you can see, the answer is the option mentioned before.