A builder set up a wooden frame in which to pour concrete for a foundation to a house. the length of the wooden frame is 24 feet. The width is 32 feet. The diagonal is 40 feet. Which best describes the foundation?

A builder set up a wooden frame in which to pour concrete for a foundation to a house the length of the wooden frame is 24 feet The width is 32 feet The diagona class=

Respuesta :

The answer is the last option, which is: The foundation may be a rectangle: [tex] 24^{2}+ 32^{2} =40^{2} [/tex]

The explanation for this problem is shown below:

1- A rectangle is defined as a parallelogram whose opposite sides are parallel and congruent. Its interior angles are right angles.

2- Keeping the definition above on mind, the diagonal of a rectangle divides it into to right triangles. So, we can verify if the shape of the frame is a rectangle by using the Pythagorean Theorem, which is:

[tex] a^{2}= b^{2} +c^{2} [/tex]

Where [tex] a [/tex] is the hypotenuse (the measure of the diagonal) and [tex] b [/tex] and [tex] c [/tex] are the other sides of the right triangle.

3- Therefore, you have that [tex] a [/tex] must be equal to [tex] 40 [/tex] to conclude that it is a rectangle:

[tex] \\a=\sqrt{24^{2}+32^{2}} \\ a=40 [/tex]

4-So, as you can see, the answer is the option mentioned before.

Answer:

The correct answer is attached below!

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