Question

[20 Points and Brainliest]
Drag the tiles to the correct boxes to complete the pairs.
Use a(x) and b(x) shown below to evaluate the given expressions.

a(x) = 3x - 1
b(x) = 2x

Tiles:
3x - 1 - 2^2x
2^x ⋅ (6x - 2)
2^x/6x - 2
3x - 1 + 2(2^x)
6x - 2 + 2^x

Boxes to match tiles with:
a(x) - b(2x)
2a(x) ⋅ b(x)
a(x) + 2b(x)
b(x)/2a(x)
2a(x) + b(x)

Answer 1

This is the answer to this problem, I had it as well but i even tually figured it out.

Answer 2

Answer:

         Tiles                                             Boxes

$3x-1-2(2^{x})$                                  $a(x)-2b(x)$

$2^x\cdot (6x-2)$                                         $2a(x)\cdot b(x)$

$\frac{2^x}{6x-2}$                                                       $\frac{b(x)}{2a(x)}$

$6x-2+2^x$                                         $2a(x)-b(x)$

$6x-2+2^x$                                         $2a(x)+b(x)$

Step-by-step explanation:

The given function are

$a(x)=3x-1$

$b(x)=2^x$

1.

$a(x)-b(2x)=3x-1-2^{2x}$

2.

$2a(x)\cdot b(x)=2(3x-1)\cdot 2^x=2^x\cdot (6x-2)$

3.

$a(x)-2b(x)=3x-1-2(2^{x})$

4.

$\frac{b(x)}{2a(x)}=\frac{2^x}{2(3x-1)}=\frac{2^x}{6x-2}$

5.

$2a(x)+b(x)=2(3x-1)+2^{x}=6x-2+2^x$

So, the required matching is

         Tiles                                             Boxes

$3x-1-2(2^{x})$                                  $a(x)-2b(x)$

$2^x\cdot (6x-2)$                                         $2a(x)\cdot b(x)$

$\frac{2^x}{6x-2}$                                                         $\frac{b(x)}{2a(x)}$

$6x-2+2^x$                                         $2a(x)-b(x)$

$6x-2+2^x$                                         $2a(x)+b(x)$