Question

What is the probability of rolling a number greater than or equal to 8 with the sum of twice dice, given that at least one of the dice must show a 6?

Answer 1

$|\Omega|=6^2=36\\ |A|=1\cdot5\cdot2!-1=9\\\\ P(A)=\dfrac{9}{36}=\dfrac{1}{4}=25\%$