Question

find the value of x. if necessary, round to the nearest tenth a=47sq in

Answer 1

the picture in the attached figure

we know that

area of the triangle is equal to

$A=(b*h)/2$

in this problem

A=47 in²

b=x

h=x

so

$47=x*x/2 \\ x^{2} =94 \\ x= \sqrt{94} \\ x=9.69 in \\ x=9.7in$

therefore

the answer is

x=9.7 in

Answer 2

The answer is 9.7 in

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