Question

he equation of the graphed line in point-slope form is , and its equation in slope-intercept form is

Answer 1

Part one is
$\frac{3}{5}$

Part two is
$y = \frac{3}{5}x - 1.8$

Answer 2

Answer:

Equation in point-slope form : $(y-0)=\frac{-3}{5}(x-3)$

Equation in Slope-intercept form : $y=\frac{-3}{5}x+\frac{9}{5}$

Step-by-step explanation:

Given point on the line are ( - 2 , 3 ) and ( 3 , 0 )

We need to write the equation of line in point-slope form  and slope-intercept form.

Slope of the line = $\frac{3-0}{-2-3}=\frac{-3}{5}$

Equation in Point Slope form is written as,

$(y-y_1)=m(x-x_1)$

So, Equation in point-slope form : $(y-0)=\frac{-3}{5}(x-3)$

Equation in Slope-intercept form is written as,

$y=mx+c$

So, Equation in point-slope form :

$(y-0)=\frac{-3}{5}(x-3)$

$(y-0)=\frac{-3}{5}(x-3)$

$y=\frac{-3}{5}x-\frac{-3}{5}\times3$

$y=\frac{-3}{5}x+\frac{9}{5}$