Question

Work out the area of the rectangle give your answer as a mixed number

Answer 1

we'll first convert the mixed fractions to "improper" and then get their product, since the area of a rectangle is the product of its length and width.

$\bf \stackrel{mixed}{5\frac{1}{6}}\implies \cfrac{5\cdot 6+1}{6}\implies \stackrel{improper}{\cfrac{31}{6}} \\\\\\ \stackrel{mixed}{2\frac{2}{7}}\implies \cfrac{2\cdot 7+2}{7}\implies \stackrel{improper}{\cfrac{16}{7}} \\\\\\ \cfrac{31}{6}\cdot \cfrac{16}{7}\implies \cfrac{496}{42}\implies \stackrel{simplified}{\cfrac{248}{21}}\implies 11\frac{17}{21}$

Answer 2

Area of the rectangle in mixed fraction is

$11\frac{17}{21} \; \; cm^2$

Given :

From the given figure , the length of the rectangle is $5\frac{1}{6} cm$

Width of the rectangle is $2\frac{2}{7}$

Now we find out the area of the rectangle using formula

$Area = length \cdot width$

First we convert mixed fractions into improper fractions

$5\frac{1}{6} =\frac{5 \cdot 6+1}{6} =\frac{31}{6}$

$2\frac{2}{7}=\frac{2 \cdot 7+2}{7} =\frac{16}{7}$

Now we find out the area

$Area = length \cdot width\\Area =\frac{31}{6} \cdot \frac{16}{7} \\Area =\frac{496}{42} \\Simplify \; it \\Area =\frac{248}{21}=11\frac{17}{21}$

Area of the rectangle is $11\frac{17}{21} \; \; cm^2$

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