Respuesta :
Answer:
[tex]y = 2(x-2)^2+4[/tex] is the equations the parabola
Step-by-step explanation:
The standard equation of parabola is given by:
[tex]y = a(x-h)^2+k[/tex] ....[1]
where,
a is the non zero real number and
(h, k) is the vertex of the parabola.
As per the statement:
The vertex if the parabola below is at the point (2,4)
⇒[tex](h, k) = (2, 4)[/tex]
⇒h =2 and k =4
Substitute these in [1] we have;
[tex]y = a(x-2)^2+4[/tex]
Since, the point (3,6) is on the parabola
⇒x = 3 and y = 6
then;
[tex]6 = a(3-2)^2+4[/tex]
[tex]6 = a+4[/tex]
Subtract 4 from both sides we have:
2= a
or
a = 2
⇒[tex]y = 2(x-2)^2+4[/tex]
Therefore, the equations the parabola is, [tex]y = 2(x-2)^2+4[/tex]