Respuesta :

I think the equation is 2(x-2)^2+4

Answer:

[tex]y = 2(x-2)^2+4[/tex]  is the equations the parabola

Step-by-step explanation:

The standard equation of parabola is given by:

[tex]y = a(x-h)^2+k[/tex]           ....[1]

where,

a is the non zero real number and

(h, k) is the vertex of the parabola.

As per the statement:

The vertex if the parabola below is at the point (2,4)

⇒[tex](h, k) = (2, 4)[/tex]

⇒h =2 and k =4

Substitute these in [1] we have;

[tex]y = a(x-2)^2+4[/tex]

Since, the point (3,6) is on the parabola

x = 3 and y = 6

then;

[tex]6 = a(3-2)^2+4[/tex]

[tex]6 = a+4[/tex]

Subtract 4 from both sides we have:

2= a

or

a = 2

⇒[tex]y = 2(x-2)^2+4[/tex]

Therefore, the equations the parabola is, [tex]y = 2(x-2)^2+4[/tex]

ACCESS MORE
EDU ACCESS