Respuesta :

[tex]\bf ~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{-3}x\stackrel{\stackrel{c}{\downarrow }}{+1}=0 \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ x= \cfrac{ -(-3) \pm \sqrt { (-3)^2 -4(1)(1)}}{2(1)}\implies x=\cfrac{3\pm\sqrt{9-4}}{2} \\\\\\ x=\cfrac{3\pm\sqrt{5}}{2}[/tex]
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