Question

if the sum of x√48 and 4√3 is 16√3, what is the value of x

Answer 1

x=8 
When you plug 3 into x the sum of the first equation is 27.7128129211. The second equation equals 27.712819211 as well.

Answer 2

Answer:
x = 3

Explanation:
Before we begin, remember the following:
x√a + y√a = (x+y)√a
√xy = √x * √y

The given equation is:
$x$$\sqrt{48}$ + $4 \sqrt{3}$ = $16\sqrt{3}$

Now, we know that:
48 = 16*3
Therefore:
$\sqrt{48}$ can be written as $\sqrt{16*3}$
We also know that:
$\sqrt{16} = 4$
Therefore:
$\sqrt{16*3} = \sqrt{16} * \sqrt{3} = 4 \sqrt{3}$

Now, substitute with the above in the given equation, this will give us:
$x$$\sqrt{48}$ + $4 \sqrt{3}$ = $16\sqrt{3}$
x($4 \sqrt{3} + 4 \sqrt{3} = 16 \sqrt{3} \\ 4x \sqrt{3} + 4 \sqrt{3} = 16 \sqrt{3}$

Based on the rules mentioned earlier, we can conclude that:
4x + 4 = 16
4x = 16-4
4x = 12
x = 3

Hope this helps :)