Respuesta :
For the function
f(x) = 4^(x-1) +2
the average rate of change on the interval [1, 2] is found by computing
(f(2) - f(1))/(2 - 1)
= ((4^1+2) - (4^0+2)/1
= (6-3)
= 3
f(x) = 4^(x-1) +2
the average rate of change on the interval [1, 2] is found by computing
(f(2) - f(1))/(2 - 1)
= ((4^1+2) - (4^0+2)/1
= (6-3)
= 3
Answer:
Option B is correct.
Average rate of change from x=1 to x=2 is 3
Step-by-step explanation:
Formula for Average rate of change: The ratio of the difference in the function f(x) as it changes from a to b to the difference between a and b :
[tex]A(x) = \frac{f(b)-f(a)}{b-a}[/tex]
As per the statement:
[tex]f(x) = 4^{x-1} +2[/tex]
Calculate the average rate of change from x =1 to x =2
At x = 1
[tex]f(1) = 4^{1-1} +2 = 1 +2 = 3[/tex]
At x = 2
[tex]f(2) = 4^{2-1} +2 = 4^1 +2 = 4+2 =6[/tex]
Then;
[tex]A(x) = \frac{f(2)-f(1)}{2-1} = \frac{6-3}{1} =\frac{3}{1} = 3[/tex]
Therefore, the average rate of change from x=1 to x=2 is 3