Question

A 50.0 ml sample of 0.436 m nh4no3 is diluted with water to a total volume of 250.0 ml. what is the ammonium nitrate concentration in the resulting solution?

Answer 1

Answer : The concentration of the resulting solution will be 0.0872 moles.

Explanation: As the two volumes are given and one of the moles concentration needs to be found.

So, according to the formula :- $m_{1} V_{1} = m_{2}V_{2}$
 
And here if we consider $m_{1}$ as 0.436 moles and $V_{1}$ as 50 mL then we need to find $m_{2}$ as $V_{2}$ is given as 250 mL.

So, by solving we get $m_{2} = (0.436 X 50) / 250$ = 0.0872 moles.

Answer 2

Concentration of moles are defined as the number of moles in per litre of solution. The  concentration of the resulting solution will be 0.0872 moles.

Given that,

• Volumes of solution 1 = 50 mL
• Volume of solution 2 = 250mL
• According to the formula = m$_1$V$_1$ = m$_2$V$_2$

where,

• m1 is the moles of solution 1 = 0.436
• m2 is the moles of solution 2 = ?

Now, substituting the values in the above formula we get:

$\begin{aligned}\text{m}_2&=\frac{\text{m}_1\times\text{v}_1}{\text{v}_2}\\\\&=\frac{0.436\times50}{250}\\\\&=0.0872\end{aligned}$

Therefore, the number of moles in solution 2 is 0.0872 moles.

To know more about concentration of moles, refer to the following link:

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