Question

If a hockey stick exerts a force of 40 n on a 0.5-kg puck, what will the resulting acceleration be?

Answer 1

2nd Newton's law:

F=ma
40N = 0.5 kg * a
a=40N/0.5kg =80 N/kg = 80 (kg*m/s²)/kg = 80 m/s²

Answer 2

Answer: The acceleration of the puck is $80m/s^2$

Explanation:

Force is defined as the push or pull on an object with some mass that causes change in its velocity.

It is also defined as the mass multiplied by the acceleration of the object.

Mathematically,

$F=m\times a$

where,

F = force exerted on the puck = 40 N

m = mass of the puck = 0.5 kg

a = acceleration of the puck

Putting values in above equation, we get:

$40kg.m/s^2=0.5kg\times a\\\\a=\frac{40}{0.5}=80m/s^2$

Hence, the acceleration of the puck is $80m/s^2$