The natural numbers from 1 to 10 are the positive integers from 1 to 10, so ten numbers: 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10.
The numbers in that list that are either even or 7 are: 2, 4, 6, 7, 8, 10, or six of the numbers from the original list. That means the probability that a randomly chosen natural number between 1 to 10 is either even or seven is 6 over 10:
[tex] P(even \:or\: 7) = \frac{6}{10} = \frac{3}{5} [/tex]
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Answer: [tex]P(even \:or\: 7) = \frac{3}{5} [/tex]
