I suppose you have to find the four numbers. If [tex]x[/tex] is the smallest of the four, then the next three numbers are [tex]x+2[/tex], [tex]x+4[/tex], and [tex]x+6[/tex]. The mean is 15, so
[tex]\dfrac{x+(x+2)+(x+4)+(x+6)}4=\dfrac{4x+12}4=15[/tex]
[tex]\implies x+3=15[/tex]
[tex]\implies x=12[/tex]
So the four numbers are 12, 14, 16, and 18.