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The number of ml of isopropyl alcohol that are 1 pint (473 Ml) is 331.1 Ml
calculation
assume that the 1 pint is in a container
This implies that the 1 pint (473 ml) is in 100 % M/V
what about 70 %(M/V)
that is 473 Ml = 100 %
? = 70 %
by cross multiplication
= 473 x70/100 = 331.1 Ml
calculation
assume that the 1 pint is in a container
This implies that the 1 pint (473 ml) is in 100 % M/V
what about 70 %(M/V)
that is 473 Ml = 100 %
? = 70 %
by cross multiplication
= 473 x70/100 = 331.1 Ml
There are 331.10 milliliters of isopropyl alcohol are in a 1 pint (473 ml) container.
Since rubbing alcohol is 70% (m / v) isopropyl alcohol by volume, to determine how many ml of isopropyl alcohol are in a 1 pint (473 ml) container, the following calculation must be performed:
- 473 x 70/100 = X
- 473 x 0.7 = X
- 331.1 = X
Therefore, there are 331.10 milliliters of isopropyl alcohol are in a 1 pint (473 ml) container.
Learn more about proportions in https://brainly.com/question/25640375