A pole 3 m high has a shadow 5 m long when the shadow of a nearby building is 110 m long. How tall is the building? Which of the following proportions could be used to solve the problem? 3/110 = x/5 3/x = 110/5 x/3 = 110/5

Respuesta :

You can use corresponding parts of the proportion as any of
  (pole:building) = (pole shadow:building shadow)
  (pole:pole shadow) = (building:building shadow)
or the reverse of these.

The appropriate choice is ...
  x/3 = 110/5 . . . . (building:pole) = (building shadow:pole shadow)

Answer:

[tex]\frac{110}{5}=\frac{x}{3}[/tex]

Step-by-step explanation:

Given : A pole 3 m high has a shadow 5 m long

           The shadow of a nearby building is 110 m long.

To Find:  How tall is the building?

Solution:

Let the height of building be x

A pole 3 m high has a shadow 5 m long

The shadow of a nearby building is 110 m long.

Height of pole and length of shadow has direct variation

So, A.T.Q

[tex]\frac{3}{5}=\frac{x}{110}[/tex]

or

[tex]\frac{110}{5}=\frac{x}{3}[/tex]

Hence Option C is correct

[tex]\frac{110}{5}=\frac{x}{3}[/tex]

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