Question

☺️☺️does anyone know☺️

Answer 1

The standard form of a circle:
$(x-h)^2+(y-k)^2=r^2$
Where:
(h; k) - the coordinates of a centerr - the radius
We have: $(x+5)^2+(y-10)^2=121$
therefore
$(-5;\ 10)$ - the center
$r^2=121\to r=\sqrt{121}\to r=11$ - the radius
Answer: 11

Answer 2

The answer is 11. The radius of the circle is 11 because in the equation (x-h)^2=(y-k)^2=r^2, we take the square root of the constant term on the outside to get the radius. The equation given can be rewritten as (x+5)^2+(y-10)^2=(11)^2.