Respuesta :
[tex]f(x)=3(x+5)+\dfrac{4}{x}\\\\\text{substitute x=a+2 to the equation of the function}\\\\f(a+2)=3(a+2+5)+\dfrac{4}{a+2}=3(a+7)+\dfrac{4}{a+2}=3a+21+\dfrac{4}{a+2}[/tex]
Answer:
[tex]f(a+2)=3a+21+\frac{4}{a+2}[/tex]
Step-by-step explanation:
If [tex]f(x)=3(x+5)+\frac{4}{x}[/tex]
Then we have to find f(a + 2)
Now we replace x by (a + 2) in the given expression.
f(a + 2) = 3[(a + 2) + 5] + [tex]\frac{4}{a+2}[/tex]
= 3(a + 7) + [tex]\frac{4}{a+2}[/tex]
= 3a + 21 + [tex]\frac{4}{a+2}[/tex]
So the answer is [tex]f(a+2)=3a+21+\frac{4}{a+2}[/tex]