Respuesta :

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[tex]f(x)=3(x+5)+\dfrac{4}{x}\\\\\text{substitute x=a+2 to the equation of the function}\\\\f(a+2)=3(a+2+5)+\dfrac{4}{a+2}=3(a+7)+\dfrac{4}{a+2}=3a+21+\dfrac{4}{a+2}[/tex]

Answer:

[tex]f(a+2)=3a+21+\frac{4}{a+2}[/tex]

Step-by-step explanation:

If [tex]f(x)=3(x+5)+\frac{4}{x}[/tex]

Then we have to find f(a + 2)

Now we replace x by (a + 2) in the given expression.

f(a + 2) = 3[(a + 2) + 5] + [tex]\frac{4}{a+2}[/tex]

           = 3(a + 7) + [tex]\frac{4}{a+2}[/tex]

           = 3a + 21 + [tex]\frac{4}{a+2}[/tex]

So the answer is [tex]f(a+2)=3a+21+\frac{4}{a+2}[/tex]

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