The bottom of a container has an area of 25 cm2. If 6.5 newtons of water are poured into the container, what is the pressure exerted on the bottom? 0.26 N/cm2 3.8 N/cm2 2.6 N/cm2 162.5 N/cm2

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0.26 N WELCOME
its too short so i got to write more ok bye

Answer: 0.26 N/cm2

Explanation:

The pressure exerted on the bottom of the container is given by the ratio between the force exerted (the weight of the water) and the area of the container:

[tex]p=\frac{F}{A}[/tex]

In this case:

F=6.5 N is the weight of the water

[tex]A=25 cm^2[/tex] is the area of the bottom of the container

Substituting, we find

[tex]p=\frac{6.5 N}{25 cm^2}=0.26 N/cm^2[/tex]

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